Mastering Inequality: $7x - 8(3x - 9/8) < 4$

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Mastering Inequality: $7x - 8(3x - 9/8) < 4$

Hey guys, ever looked at a math problem like 7xβˆ’8(3xβˆ’9/8)<47x - 8(3x - 9/8) < 4 and thought, "Ugh, where do I even begin?" You're definitely not alone! Inequalities can seem a bit intimidating at first, especially with all those numbers, variables, and that sneaky inequality sign. But trust me, once you break them down, they're not nearly as scary as they look. In fact, solving them is a super valuable skill, not just for passing your math class but for tackling real-world scenarios where things aren't always perfectly equal. Think about it: setting a budget, managing time, or even figuring out the best deal when shoppingβ€”all these involve inequalities! Today, we're going to dive deep into this specific inequality, unraveling each step with a friendly, casual approach. Our goal isn't just to find the answer, but to truly understand why we do each step, equipping you with the confidence to tackle any similar problem that comes your way. So, grab your virtual pen and paper, and let's conquer this inequality together, building a rock-solid foundation for your math journey.

Understanding Inequalities: More Than Just Equations

Understanding inequalities is fundamentally about grasping that not everything in life, or math, is about perfect equality. Unlike equations, which typically aim to find a single, precise value for a variable (like x=5x = 5), inequalities deal with ranges of values. They tell us that a variable could be greater than, less than, greater than or equal to, or less than or equal to a certain number. This distinction is hugely important because it shifts our perspective from a single point on a number line to an entire section of it. Think of it like this: an equation is asking, "What's the exact temperature that boils water?" (212Β°F or 100Β°C), while an inequality asks, "What temperatures are too hot to touch?" (anything above, say, 120Β°F). See the difference? One is a fixed point, the other is a vast domain. The real world is overflowing with situations best described by inequalities. Imagine you're planning a party and you have a budget of $500. You don't just spend exactly $500; you need to spend $500 or less (expenses ≀\le 500). Or, consider driving on a highway where the speed limit is 65 mph. You must drive at a speed _less than or equal to_ 65 mph (speed ≀\le 65). Your doctor might tell you your cholesterol level needs to be less than 200 mg/dL (cholesterol <200< 200). These aren't about exact numbers; they're about boundaries and acceptable ranges. The underlying principles for solving linear inequalities, like the one we're tackling, are strikingly similar to solving linear equations. You're still aiming to isolate the variable, moving terms around to get 'x' by itself. You'll use inverse operations: addition undoes subtraction, multiplication undoes division. However, there's one major, critical rule that makes inequalities unique and often a source of common errors: when you multiply or divide both sides of an inequality by a negative number, you MUST flip the direction of the inequality sign. This little detail is a game-changer, and we'll dive deeper into why this happens when we get to that step. Building a strong foundation in these basic concepts is key, because once you've mastered linear inequalities, you'll be well-prepared to tackle more complex ones, like quadratic inequalities or those involving absolute values, making your mathematical journey smoother and much more enjoyable. So, let's keep these foundational ideas in mind as we roll up our sleeves and get to work on our specific problem.

Step-by-Step Breakdown: Conquering Our Specific Inequality

Alright, it's time to face our specific challenge head-on: 7xβˆ’8(3xβˆ’9/8)<47x - 8(3x - 9/8) < 4. Our ultimate goal here, just like with equations, is to simplify this expression and then isolate the variable 'x' to find out which values of 'x' make this statement true. We're going to take it one careful step at a time, making sure we understand the logic behind each move. No rushing, no shortcuts, just pure, methodical problem-solving. This approach not only helps us arrive at the correct answer but also minimizes the chances of making those pesky little arithmetic or sign errors that can completely derail a solution. Think of it like building a Lego set; you follow the instructions piece by piece, ensuring each connection is solid before moving on to the next. By dissecting this inequality into manageable chunks, we’ll see that even complex-looking problems are just a series of familiar algebraic operations. Let's start by addressing the most obvious part that needs attention: those parentheses that are grouping some terms together. Getting rid of them will be our first priority, paving the way for combining like terms and simplifying the expression significantly.

Step 1: Distribute and Conquer Parentheses

Our first major move in solving this inequality is to distribute and conquer those parentheses. Remember the distributive property from your algebra classes? It's our best friend here! The distributive property states that a(bβˆ’c)=abβˆ’aca(b - c) = ab - ac. In our inequality, 7xβˆ’8(3xβˆ’9/8)<47x - 8(3x - 9/8) < 4, the term outside the parentheses is βˆ’8-8. It's super important to include the negative sign with the 8. This βˆ’8-8 needs to be multiplied by each term inside the parentheses. So, we'll multiply βˆ’8-8 by 3x3x, and then we'll multiply βˆ’8-8 by βˆ’9/8-9/8. Let's break down those multiplications carefully. First, βˆ’8imes3x-8 imes 3x gives us βˆ’24x-24x. That was straightforward, right? Now, for the second part, we have βˆ’8imesβˆ’9/8-8 imes -9/8. This is where paying close attention to signs is crucial! A negative number multiplied by a negative number always results in a positive number. Also, notice that we have an 8 in the numerator and an 8 in the denominator; they beautifully cancel each other out. So, βˆ’8imesβˆ’9/8-8 imes -9/8 simplifies to just +9+9. See how much simpler that became? After performing this distribution, our inequality transforms from its original form into something much more manageable. The inequality now looks like this: 7xβˆ’24x+9<47x - 24x + 9 < 4. By eliminating the parentheses, we've removed a layer of complexity and brought all our 'x' terms and constant terms out into the open, ready for the next phase of simplification. This step is a cornerstone of solving many algebraic expressions, as getting rid of grouping symbols is almost always the very first thing you want to do to tidy things up and prepare for combining terms.

Step 2: Combine Like Terms – Simplify the Left Side

With the parentheses out of the way, our next logical step is to combine like terms on the left side of the inequality. Our current inequality is 7xβˆ’24x+9<47x - 24x + 9 < 4. "Like terms" are simply terms that have the same variable raised to the same power. In this case, we have two 'x' terms: 7x7x and βˆ’24x-24x. The '9' is a constant term, which means it doesn't have a variable attached, so it's not a like term with 7x7x or βˆ’24x-24x. Combining like terms means performing the indicated operations on their coefficients (the numbers in front of the variables). Here, we need to subtract 24x24x from 7x7x. So, 7xβˆ’24x7x - 24x. Think of it as 7βˆ’247 - 24. When you subtract a larger number from a smaller number, your result will be negative. The difference between 24 and 7 is 17, so 7βˆ’247 - 24 equals βˆ’17-17. Therefore, 7xβˆ’24x7x - 24x simplifies to βˆ’17x-17x. Our inequality has now become even more streamlined: βˆ’17x+9<4-17x + 9 < 4. This step is all about tidying up our expression, consolidating multiple terms into fewer, more manageable ones. It’s like organizing your workspace; by grouping similar tools or papers together, you make the whole setup much more efficient and easier to work with. The fewer terms we have, the clearer the path becomes to isolating our variable 'x', which is our ultimate goal. Keeping track of the signs throughout this process is absolutely essential, as a single misplaced negative can throw off your entire solution. Always double-check your addition and subtraction of integers. We're getting closer to isolating 'x'!

Step 3: Isolate the Variable Term – Move Constants

Now that we've simplified the left side of our inequality to βˆ’17x+9<4-17x + 9 < 4, our next crucial step is to isolate the variable term. This means we want to get the term containing 'x' (which is βˆ’17x-17x) all by itself on one side of the inequality. To achieve this, we need to get rid of the constant term that's currently hanging out with βˆ’17x-17x. In our case, that constant term is +9+9. To move a term from one side of an inequality to the other, we perform the inverse operation. Since we have +9+9 on the left, the inverse operation is to subtract 99. And, just like with equations, whatever we do to one side of the inequality, we must do to the other side to keep the statement balanced and true. So, we'll subtract 99 from both sides of our inequality. On the left side, we'll have βˆ’17x+9βˆ’9-17x + 9 - 9, which simplifies beautifully to just βˆ’17x-17x. The +9+9 and βˆ’9-9 cancel each other out, leaving us exactly what we wanted! On the right side, we perform the subtraction: 4βˆ’94 - 9. This calculation results in βˆ’5-5. So, after this step, our inequality has been transformed once again, now looking like this: βˆ’17x<βˆ’5-17x < -5. Notice that the inequality sign has not changed direction in this step. This is because adding or subtracting a number from both sides of an inequality never affects the direction of the inequality sign. That special rule about flipping the sign only applies when you multiply or divide by a negative number, which is coming up next! This step effectively separates the variable terms from the constant terms, laying the groundwork for the grand finale of isolating 'x'.

Step 4: The Big Reveal – Divide and Potentially Flip the Sign!

Here we are, at the most critical step when solving inequalities: the moment we divide and potentially flip the sign! Our inequality has been boiled down to βˆ’17x<βˆ’5-17x < -5. Our ultimate goal is to get 'x' completely by itself, meaning we need to get rid of that βˆ’17-17 that's currently multiplying 'x'. To do this, we'll perform the inverse operation: division. We need to divide both sides of the inequality by βˆ’17-17. Now, pay extremely close attention here, because this is where inequalities differ fundamentally from equations and where many students make mistakes. There's a golden rule for inequalities: If you multiply or divide both sides of an inequality by a negative number, you MUST flip the direction of the inequality sign. Seriously, guys, tattoo this rule into your brain! Since we are dividing by a negative number (specifically, βˆ’17-17), we absolutely have to flip the sign. Let's execute the division. On the left side, βˆ’17x-17x divided by βˆ’17-17 simply gives us xx. Perfect, 'x' is now isolated! On the right side, we have βˆ’5-5 divided by βˆ’17-17. A negative divided by a negative results in a positive, so βˆ’5/βˆ’17-5 / -17 becomes 5/175/17. And now for the crucial part: because we divided by βˆ’17-17 (a negative number), the 'less than' sign (<<) flips and becomes a 'greater than' sign (>>). So, our final, glorious solution is: x>5/17x > 5/17. To truly understand why the sign flips, consider a simpler example: we know that 2<52 < 5 is true, right? Now, if we multiply both sides by βˆ’1-1, we get βˆ’2-2 and βˆ’5-5. Is βˆ’2<βˆ’5-2 < -5 true? No way! βˆ’2-2 is actually greater than βˆ’5-5 on the number line. So, to keep the statement true, we must flip the sign: βˆ’2>βˆ’5-2 > -5. This same logic applies when dividing by a negative number. This step is the grand finale, giving us the range of values for 'x' that satisfies the original inequality, and understanding why the sign flips is as important as remembering to flip it.

Verifying Your Solution: Don't Just Solve, Check!

Once you've arrived at a solution like x>5/17x > 5/17, it's super tempting to just pat yourself on the back and move on. But hold up, guys! A true math pro always takes the time to verify their solution. Verifying your solution is not just about catching potential errors; it's about building confidence in your work, deepening your understanding of the inequality, and ensuring absolute accuracy. It's your personal error-detection system! The beauty of checking an inequality solution is that you can pick values from your solution set and values outside of it to see if they make the original statement true or false, respectively. Our solution is x>5/17x > 5/17. To get a better sense of this fraction, 5/175/17 is approximately 0.2940.294. So, our solution states that 'x' must be any number greater than approximately 0.2940.294. Let's try two test values: one that should work (a value greater than 5/175/17) and one that should not work (a value less than or equal to 5/175/17).

Test Value 1: Pick a value where x>5/17x > 5/17. Let's choose a simple integer, like x=1x = 1. Since 11 is clearly greater than 5/175/17, this value should make the original inequality true. Substitute x=1x=1 back into the original inequality: 7xβˆ’8(3xβˆ’9/8)<47x - 8(3x - 9/8) < 4.

7(1)βˆ’8(3(1)βˆ’9/8)<47(1) - 8(3(1) - 9/8) < 4 7βˆ’8(3βˆ’9/8)<47 - 8(3 - 9/8) < 4 7βˆ’8(24/8βˆ’9/8)<47 - 8(24/8 - 9/8) < 4 (We found a common denominator for the terms inside the parentheses) 7βˆ’8(15/8)<47 - 8(15/8) < 4 7βˆ’15<47 - 15 < 4 (The 8s cancel out here) βˆ’8<4-8 < 4

Is βˆ’8<4-8 < 4 a true statement? Absolutely! This confirms that our solution of x>5/17x > 5/17 is on the right track, at least for this particular value.

Test Value 2: Pick a value where xot>5/17x ot> 5/17. Let's choose x=0x = 0. Since 00 is less than 5/175/17, this value should not make the original inequality true. Substitute x=0x=0 back into the original inequality: 7xβˆ’8(3xβˆ’9/8)<47x - 8(3x - 9/8) < 4.

7(0)βˆ’8(3(0)βˆ’9/8)<47(0) - 8(3(0) - 9/8) < 4 0βˆ’8(0βˆ’9/8)<40 - 8(0 - 9/8) < 4 0βˆ’8(βˆ’9/8)<40 - 8(-9/8) < 4 0+9<40 + 9 < 4 (Again, negative times negative is positive, and 8s cancel) 9<49 < 4

Is 9<49 < 4 a true statement? Definitely not! This false result perfectly aligns with our solution, as x=0x=0 falls outside the x>5/17x > 5/17 range. Both test cases work exactly as expected, providing strong evidence that our final solution, x>5/17x > 5/17, is correct. You can also express this solution in interval notation as (5/17,extinfinity)(5/17, ext{infinity}), or visually represent it on a number line with an open circle at 5/175/17 and an arrow extending to the right, indicating all numbers greater than 5/175/17. This verification step is invaluable for solidifying your grasp of inequalities and ensures you submit accurate answers every time.

Common Pitfalls and Pro Tips for Inequality Solvers

Alright, you've mastered the steps, but let's talk about how to truly become an inequality wizard and avoid those sneaky traps that can trip even the best of us up. Learning from common errors and equipping yourself with some pro tips for inequality solvers can make a huge difference in your success and confidence. Being aware of these pitfalls beforehand is like having a cheat sheet for avoiding mistakes.

Common Pitfall 1: Forgetting to Flip the Sign. Guys, I can't stress this enough! This is, without a doubt, the number one mistake students make. We hammered it home in Step 4, but it's worth repeating: ALWAYS flip the inequality sign when you multiply or divide both sides by a negative number. Period. No exceptions. Just a quick reminder: if you have βˆ’2x>10-2x > 10, you divide by βˆ’2-2, and it becomes x<βˆ’5x < -5. Don't let this tiny detail sabotage your hard work!

Common Pitfall 2: Sign Errors During Distribution. Remember our first step, distributing the βˆ’8-8? It's easy to accidentally miss a negative sign. Forgetting that βˆ’8imesβˆ’9/8-8 imes -9/8 yields a positive 99, instead of a negative, is a very common error. Always double-check your multiplication with negative numbers; a negative times a negative is positive, and a negative times a positive is negative. Be meticulously careful with every single sign!

Common Pitfall 3: Arithmetic Mistakes. Sometimes, it's not the fancy algebra that gets you, but simple addition or subtraction. Miscalculating 7βˆ’247 - 24 or 4βˆ’94 - 9 can throw off your entire solution. Take your time, use a calculator if allowed, or even count on your fingers for those basic integer operations. It's often the small, basic errors that lead to a completely wrong answer.

Common Pitfall 4: Rushing Through Steps. Math isn't a race! Each step builds upon the previous one. If you rush, you're more likely to skip a crucial sign flip, miscalculate, or combine terms incorrectly. Break down the problem, take a deep breath, and approach each step methodically. Showing your work clearly (which is our first pro tip!) can help prevent this.

Now for some Pro Tips to make you an inequality-solving superstar:

Pro Tip 1: Show Your Work, Step by Step! This isn't just for your teacher; it's for you. Writing out each transformation of the inequality on a new line makes it incredibly easy to track your progress, spot errors, and understand exactly where things went right (or wrong). It also acts as a visual guide to ensure you're performing inverse operations correctly.

Pro Tip 2: Use Parentheses for Clarity, Especially with Negatives. When substituting values back into the original inequality to check your solution, always put the substituted number in parentheses. This helps prevent sign errors and clarifies the order of operations, especially when dealing with negative numbers being multiplied or squared.

Pro Tip 3: Visualize with a Number Line. After finding your solution (like x>5/17x > 5/17), mentally or physically sketch it on a number line. An open circle at 5/175/17 with an arrow pointing right for x>5/17x > 5/17. This visual representation helps solidify your understanding of the solution set and makes it easier to pick appropriate test values.

Pro Tip 4: Practice, Practice, Practice! There's no substitute for repetition. The more inequalities you solve, the more intuitive the rules become, especially that crucial sign-flipping rule. Start with simpler problems and gradually work your way up to more complex ones.

Pro Tip 5: Connect to Real Life. Whenever possible, try to think about what the inequality's solution means in a practical context. If 'x' represented your budget, what does x>5/17x > 5/17 mean? Connecting math to the real world makes it more engaging and helps reinforce the concepts.

Pro Tip 6: Review Foundational Algebra. If you find yourself consistently struggling, it might be a sign that some foundational algebra concepts need a quick refresh. Go back to basics like combining like terms, the distributive property, and integer arithmetic. A solid foundation makes all future math problems much easier.

By keeping these pitfalls in mind and applying these pro tips, you'll not only solve inequalities more accurately but also develop a deeper, more confident understanding of algebraic problem-solving. You've got this!

Wrapping It Up

Well, there you have it, folks! We've meticulously walked through every twist and turn of solving the inequality 7xβˆ’8(3xβˆ’9/8)<47x - 8(3x - 9/8) < 4. From distributing those tricky negative numbers to combining like terms, isolating the variable, and, most crucially, remembering to flip that inequality sign when dividing by a negative, we've covered it all. The final solution, x>5/17x > 5/17, represents an entire range of numbers that satisfy our original statement, and you've learned how to verify this solution with test values, giving you absolute certainty in your answer. Remember, inequalities aren't just abstract math problems; they're powerful tools for understanding limits, conditions, and possibilities in the real world. By understanding the core principles, being mindful of common pitfalls, and applying our pro tips, you're now better equipped to tackle not just this problem, but a whole universe of algebraic inequalities. Keep practicing, stay curious, and you'll continue to build that mathematical muscle. You're doing great, and I'm sure you'll conquer your next math challenge with newfound confidence!